This is a Fillomino Snake puzzle. A snake with a head and tail and unknown length must be drawn in the grid so that it contains all shaded cells. The snake does not touch itself, even at a point. The remaining spaces must be divided into polyominoes satisfying the usual Fillomino rules. The snake may touch polyominoes of the same size as itself.
Puzzle 412
Part 1 of 4 in my half of the preview series for Fillomino-Fillia 2. See mathgrant’s blog for the other half.
Answer Entry: Enter the units digits (last digit) of the number in each circled cell starting with the leftmost column and going right. For a cell with a snake segment, write X.
Highlight to see answer: 269X9722
On a related note, it seems the WordPress thumbnail issue has fixed itself. That’s a relief.
October 23, 2012 at 12:19 pm |
Nice Fillomino, and the 9s interaction. Snake seems to
October 23, 2012 at 3:17 pm |
Don’t leave me hanging!
October 23, 2012 at 4:34 pm
I think horse_ebooks hacked ksun’s account.
October 24, 2012 at 9:40 am
Snake seems to have eaten his comment up. Anyway, nice puzzle. The gateway kind of thing formed by the higher numbers in between was nice.
October 23, 2012 at 10:00 pm |
Are you going to do guess the author again? I wasn’t in the puzzlosphere last year and I think I can tell your styles apart pretty well so I hope you do.
October 23, 2012 at 10:06 pm |
The short answer is that it’s very unlikely. But you’re free to email one of us your guesses after the test anyway.
October 23, 2012 at 10:22 pm |
be somewhat more interesting. than Path in some ways, as the snake imposes some more restrictions on the Fillomino. Also, glad to see that Nonconsecutive and No-Rectangles made an appearance this year!
)
(Darn, they’re much more strict about tardiness in high school than college or middle school.
October 26, 2012 at 10:10 pm |
I quite liked the uniqueness logic in this one, particularly with the 6 and 8 in the bottom left. Well done.